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Question

Answers

A. n-x

B. n+x

C. n+2x

D. n+x.x

Answer

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Since initially the beat frequency was x, and the frequency of A is ‘n’, hence putting in the equation, we get

$\beta=|\nu_1-\nu_2|$

Or $x=|n-\nu_2|$

But, to open the mathematical sign mode, we need to know which fork has more frequency? We can easily figure it out by analyzing the statement in the question.

According to the statement, when fork B is loaded with wax, the beat frequency decreases.

This can only be possible if the frequency of fork B is greater than that of A.

Thus, $x=\nu_{B}-n$

Or $\nu_{B}=n+x$

[To understand properly, see note]

$Beat\ frequency (\beta)=\nu_1-\nu_2$

Let’s assume $\nu_2$be the frequency of B, then on decreasing $\nu_2$, $\beta$ will definitely increase. Hence our assumption is wrong. Whereas assuming $\nu_1$ being the frequency of B, then on decreasing $\nu_1$, $\beta$ will also decrease.